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2x^2+3=4x-1
We move all terms to the left:
2x^2+3-(4x-1)=0
We get rid of parentheses
2x^2-4x+1+3=0
We add all the numbers together, and all the variables
2x^2-4x+4=0
a = 2; b = -4; c = +4;
Δ = b2-4ac
Δ = -42-4·2·4
Δ = -16
Delta is less than zero, so there is no solution for the equation
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